1345160121001 has 4 divisors (see below), whose sum is σ = 1345312659600. Its totient is φ = 1345007582404.

The previous prime is 1345160120951. The next prime is 1345160121037. The reversal of 1345160121001 is 1001210615431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1345160121001 - 2³¹ = 1343012637353 is a prime.

It is a super-5 number, since 5×1345160121001⁵ (a number of 62 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1345160121091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76256071 + ... + 76273708.

It is an arithmetic number, because the mean of its divisors is an integer number (336328164900).

Almost surely, 2^{1345160121001} is an apocalyptic number.

It is an amenable number.

1345160121001 is a deficient number, since it is larger than the sum of its proper divisors (152538599).

1345160121001 is an equidigital number, since it uses as much as digits as its factorization.

1345160121001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 152538598.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1345160121001 its reverse (1001210615431), we get a palindrome (2346370736432).

The spelling of 1345160121001 in words is "one trillion, three hundred forty-five billion, one hundred sixty million, one hundred twenty-one thousand, one".