Base | Representation |
---|---|
bin | 10011100100110111011… |
… | …010010010010100111110 |
3 | 11202121100002111020022202 |
4 | 103210313122102110332 |
5 | 134020040111320332 |
6 | 2510000142311502 |
7 | 166122441512465 |
oct | 23446732222476 |
9 | 4677302436282 |
10 | 1345254401342 |
11 | 479579047785 |
12 | 198876b88592 |
13 | 99b1a92c407 |
14 | 4917991b9dc |
15 | 24ed6d66a62 |
hex | 1393769253e |
1345254401342 has 16 divisors (see below), whose sum is σ = 2021899283712. Its totient is φ = 671288487000.
The previous prime is 1345254401261. The next prime is 1345254401347. The reversal of 1345254401342 is 2431044525431.
It is a super-2 number, since 2×13452544013422 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1345254401296 and 1345254401305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1345254401347) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5223893 + ... + 5475359.
It is an arithmetic number, because the mean of its divisors is an integer number (126368705232).
Almost surely, 21345254401342 is an apocalyptic number.
1345254401342 is a deficient number, since it is larger than the sum of its proper divisors (676644882370).
1345254401342 is a wasteful number, since it uses less digits than its factorization.
1345254401342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256783.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 1345254401342 its reverse (2431044525431), we get a palindrome (3776298926773).
The spelling of 1345254401342 in words is "one trillion, three hundred forty-five billion, two hundred fifty-four million, four hundred one thousand, three hundred forty-two".
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