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1345254401342 = 25634751251467
BaseRepresentation
bin10011100100110111011…
…010010010010100111110
311202121100002111020022202
4103210313122102110332
5134020040111320332
62510000142311502
7166122441512465
oct23446732222476
94677302436282
101345254401342
11479579047785
12198876b88592
1399b1a92c407
144917991b9dc
1524ed6d66a62
hex1393769253e

1345254401342 has 16 divisors (see below), whose sum is σ = 2021899283712. Its totient is φ = 671288487000.

The previous prime is 1345254401261. The next prime is 1345254401347. The reversal of 1345254401342 is 2431044525431.

It is a super-2 number, since 2×13452544013422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1345254401296 and 1345254401305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345254401347) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5223893 + ... + 5475359.

It is an arithmetic number, because the mean of its divisors is an integer number (126368705232).

Almost surely, 21345254401342 is an apocalyptic number.

1345254401342 is a deficient number, since it is larger than the sum of its proper divisors (676644882370).

1345254401342 is a wasteful number, since it uses less digits than its factorization.

1345254401342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 256783.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 1345254401342 its reverse (2431044525431), we get a palindrome (3776298926773).

The spelling of 1345254401342 in words is "one trillion, three hundred forty-five billion, two hundred fifty-four million, four hundred one thousand, three hundred forty-two".

Divisors: 1 2 563 1126 4751 9502 251467 502934 2674813 5349626 141575921 283151842 1194719717 2389439434 672627200671 1345254401342