Base | Representation |
---|---|
bin | 10011100100111000000… |
… | …010110011010011010001 |
3 | 11202121100211110211100102 |
4 | 103210320002303103101 |
5 | 134020100321202121 |
6 | 2510001202102145 |
7 | 166122631006124 |
oct | 23447002632321 |
9 | 4677324424312 |
10 | 1345265022161 |
11 | 479584041315 |
12 | 19887a64a955 |
13 | 99b1cbaa718 |
14 | 4917b0c43bb |
15 | 24ed7c6390b |
hex | 139380b34d1 |
1345265022161 has 4 divisors (see below), whose sum is σ = 1416068444400. Its totient is φ = 1274461599924.
The previous prime is 1345265022109. The next prime is 1345265022173. The reversal of 1345265022161 is 1612205625431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1345265022161 - 218 = 1345264760017 is a prime.
It is a super-2 number, since 2×13452650221612 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1345265022191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35401711091 + ... + 35401711128.
It is an arithmetic number, because the mean of its divisors is an integer number (354017111100).
Almost surely, 21345265022161 is an apocalyptic number.
It is an amenable number.
1345265022161 is a deficient number, since it is larger than the sum of its proper divisors (70803422239).
1345265022161 is an equidigital number, since it uses as much as digits as its factorization.
1345265022161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70803422238.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 1345265022161 in words is "one trillion, three hundred forty-five billion, two hundred sixty-five million, twenty-two thousand, one hundred sixty-one".
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