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1345310434003 = 6720079260209
BaseRepresentation
bin10011100100111010110…
…000000010001011010011
311202121110222220222200111
4103210322300002023103
5134020143432342003
62510005503302151
7166124022004144
oct23447260021323
94677428828614
101345310434003
114795a7738968
121988918aa957
1399b2941a633
1449183145acb
1524edbc33e6d
hex1393ac022d3

1345310434003 has 4 divisors (see below), whose sum is σ = 1365389694280. Its totient is φ = 1325231173728.

The previous prime is 1345310433989. The next prime is 1345310434033. The reversal of 1345310434003 is 3004340135431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1345310434003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1345310434033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10039630038 + ... + 10039630171.

It is an arithmetic number, because the mean of its divisors is an integer number (341347423570).

Almost surely, 21345310434003 is an apocalyptic number.

1345310434003 is a deficient number, since it is larger than the sum of its proper divisors (20079260277).

1345310434003 is an equidigital number, since it uses as much as digits as its factorization.

1345310434003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20079260276.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 1345310434003 its reverse (3004340135431), we get a palindrome (4349650569434).

The spelling of 1345310434003 in words is "one trillion, three hundred forty-five billion, three hundred ten million, four hundred thirty-four thousand, three".

Divisors: 1 67 20079260209 1345310434003