Base | Representation |
---|---|
bin | 101000000110001… |
… | …0011111110111001 |
3 | 10110202121122111112 |
4 | 1100030103332321 |
5 | 10223410423412 |
6 | 341300410105 |
7 | 45224516066 |
oct | 12014237671 |
9 | 3422548445 |
10 | 1345404857 |
11 | 63049a645 |
12 | 3166a6935 |
13 | 185974964 |
14 | ca97dc6d |
15 | 7d1ad722 |
hex | 50313fb9 |
1345404857 has 2 divisors, whose sum is σ = 1345404858. Its totient is φ = 1345404856.
The previous prime is 1345404821. The next prime is 1345404869. The reversal of 1345404857 is 7584045431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 708145321 + 637259536 = 26611^2 + 25244^2 .
It is an emirp because it is prime and its reverse (7584045431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1345404857 - 28 = 1345404601 is a prime.
It is a super-2 number, since 2×13454048572 = 3620228458478380898, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1345484857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672702428 + 672702429.
It is an arithmetic number, because the mean of its divisors is an integer number (672702429).
Almost surely, 21345404857 is an apocalyptic number.
It is an amenable number.
1345404857 is a deficient number, since it is larger than the sum of its proper divisors (1).
1345404857 is an equidigital number, since it uses as much as digits as its factorization.
1345404857 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 268800, while the sum is 41.
The square root of 1345404857 is about 36679.7608634517. The cubic root of 1345404857 is about 1103.9540499433.
The spelling of 1345404857 in words is "one billion, three hundred forty-five million, four hundred four thousand, eight hundred fifty-seven".
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