1345405433331 has 4 divisors (see below), whose sum is σ = 1793873911112. Its totient is φ = 896936955552.

The previous prime is 1345405433311. The next prime is 1345405433417. The reversal of 1345405433331 is 1333345045431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1345405433331 - 2¹⁰ = 1345405432307 is a prime.

It is a super-2 number, since 2×1345405433331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1345405433331.

It is not an unprimeable number, because it can be changed into a prime (1345405433311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224234238886 + ... + 224234238891.

It is an arithmetic number, because the mean of its divisors is an integer number (448468477778).

Almost surely, 2^{1345405433331} is an apocalyptic number.

1345405433331 is a deficient number, since it is larger than the sum of its proper divisors (448468477781).

1345405433331 is an equidigital number, since it uses as much as digits as its factorization.

1345405433331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448468477780.

The product of its (nonzero) digits is 388800, while the sum is 39.

The spelling of 1345405433331 in words is "one trillion, three hundred forty-five billion, four hundred five million, four hundred thirty-three thousand, three hundred thirty-one".