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134554004393 is a prime number
BaseRepresentation
bin111110101010000001…
…0110010101110101001
3110212022022002122020012
41331110002302232221
54201031311120033
6141451355141305
712502242111044
oct1752402625651
9425268078205
10134554004393
1152078256026
12220b1a44835
13c8c45092a3
146726231c5b
153777a6d248
hex1f540b2ba9

134554004393 has 2 divisors, whose sum is σ = 134554004394. Its totient is φ = 134554004392.

The previous prime is 134554004359. The next prime is 134554004407. The reversal of 134554004393 is 393400455431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78085036969 + 56468967424 = 279437^2 + 237632^2 .

It is an emirp because it is prime and its reverse (393400455431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134554004393 - 218 = 134553742249 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 134554004393.

It is not a weakly prime, because it can be changed into another prime (134554084393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67277002196 + 67277002197.

It is an arithmetic number, because the mean of its divisors is an integer number (67277002197).

Almost surely, 2134554004393 is an apocalyptic number.

It is an amenable number.

134554004393 is a deficient number, since it is larger than the sum of its proper divisors (1).

134554004393 is an equidigital number, since it uses as much as digits as its factorization.

134554004393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 134554004393 in words is "one hundred thirty-four billion, five hundred fifty-four million, four thousand, three hundred ninety-three".