Base | Representation |
---|---|
bin | 111110101010101111… |
… | …0100010000011100011 |
3 | 110212100222100110012012 |
4 | 1331111132202003203 |
5 | 4201103440201342 |
6 | 141454014423135 |
7 | 12502653402443 |
oct | 1752536420343 |
9 | 425328313165 |
10 | 134578053347 |
11 | 5208a8913a1 |
12 | 220b9b01aab |
13 | c8c94a963a |
14 | 67294d2123 |
15 | 3779c1db82 |
hex | 1f557a20e3 |
134578053347 has 2 divisors, whose sum is σ = 134578053348. Its totient is φ = 134578053346.
The previous prime is 134578053329. The next prime is 134578053367. The reversal of 134578053347 is 743350875431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134578053347 is a prime.
It is a super-2 number, since 2×1345780533472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134578053295 and 134578053304.
It is not a weakly prime, because it can be changed into another prime (134578053317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67289026673 + 67289026674.
It is an arithmetic number, because the mean of its divisors is an integer number (67289026674).
Almost surely, 2134578053347 is an apocalyptic number.
134578053347 is a deficient number, since it is larger than the sum of its proper divisors (1).
134578053347 is an equidigital number, since it uses as much as digits as its factorization.
134578053347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4233600, while the sum is 50.
The spelling of 134578053347 in words is "one hundred thirty-four billion, five hundred seventy-eight million, fifty-three thousand, three hundred forty-seven".
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