Base | Representation |
---|---|
bin | 111110101100001011… |
… | …1011011100000000001 |
3 | 110212111100112222020121 |
4 | 1331120113123200001 |
5 | 4201203342220022 |
6 | 141502505340241 |
7 | 12504112365001 |
oct | 1753027334001 |
9 | 425440488217 |
10 | 134626523137 |
11 | 52105187477 |
12 | 22112197681 |
13 | c90654a3a2 |
14 | 6731b0c001 |
15 | 377e0e52c7 |
hex | 1f585db801 |
134626523137 has 2 divisors, whose sum is σ = 134626523138. Its totient is φ = 134626523136.
The previous prime is 134626523113. The next prime is 134626523147. The reversal of 134626523137 is 731325626431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134515831696 + 110691441 = 366764^2 + 10521^2 .
It is a cyclic number.
It is not a de Polignac number, because 134626523137 - 219 = 134625998849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134626523093 and 134626523102.
It is not a weakly prime, because it can be changed into another prime (134626523147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67313261568 + 67313261569.
It is an arithmetic number, because the mean of its divisors is an integer number (67313261569).
Almost surely, 2134626523137 is an apocalyptic number.
It is an amenable number.
134626523137 is a deficient number, since it is larger than the sum of its proper divisors (1).
134626523137 is an equidigital number, since it uses as much as digits as its factorization.
134626523137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 544320, while the sum is 43.
The spelling of 134626523137 in words is "one hundred thirty-four billion, six hundred twenty-six million, five hundred twenty-three thousand, one hundred thirty-seven".
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