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134654600651 = 552124389531
BaseRepresentation
bin111110101101000001…
…0100010010111001011
3110212120022101110100112
41331122002202113023
54201233034210101
6141505351224535
712504603135434
oct1753202422713
9425508343315
10134654600651
115211a01452a
122211b67814b
13c90c2cb2bc
14673573a48b
1537817de6bb
hex1f5a0a25cb

134654600651 has 4 divisors (see below), whose sum is σ = 134678995704. Its totient is φ = 134630205600.

The previous prime is 134654600629. The next prime is 134654600687. The reversal of 134654600651 is 156006456431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134654600651 - 222 = 134650406347 is a prime.

It is a super-2 number, since 2×1346546006512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134654600599 and 134654600608.

It is not an unprimeable number, because it can be changed into a prime (134654600551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12189245 + ... + 12200286.

It is an arithmetic number, because the mean of its divisors is an integer number (33669748926).

Almost surely, 2134654600651 is an apocalyptic number.

134654600651 is a deficient number, since it is larger than the sum of its proper divisors (24395053).

134654600651 is an equidigital number, since it uses as much as digits as its factorization.

134654600651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24395052.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 134654600651 in words is "one hundred thirty-four billion, six hundred fifty-four million, six hundred thousand, six hundred fifty-one".

Divisors: 1 5521 24389531 134654600651