Base | Representation |
---|---|
bin | 111110101110101110… |
… | …1101100001100010001 |
3 | 110212201022111012122211 |
4 | 1331131131230030101 |
5 | 4201342241103244 |
6 | 141515202432121 |
7 | 12506201351524 |
oct | 1753535541421 |
9 | 425638435584 |
10 | 134712050449 |
11 | 521494933a9 |
12 | 22136962641 |
13 | c91b194572 |
14 | 673d212bbb |
15 | 378688b934 |
hex | 1f5d76c311 |
134712050449 has 2 divisors, whose sum is σ = 134712050450. Its totient is φ = 134712050448.
The previous prime is 134712050443. The next prime is 134712050467. The reversal of 134712050449 is 944050217431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108672419025 + 26039631424 = 329655^2 + 161368^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134712050449 is a prime.
It is a super-3 number, since 3×1347120504493 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (134712050443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67356025224 + 67356025225.
It is an arithmetic number, because the mean of its divisors is an integer number (67356025225).
Almost surely, 2134712050449 is an apocalyptic number.
It is an amenable number.
134712050449 is a deficient number, since it is larger than the sum of its proper divisors (1).
134712050449 is an equidigital number, since it uses as much as digits as its factorization.
134712050449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 134712050449 in words is "one hundred thirty-four billion, seven hundred twelve million, fifty thousand, four hundred forty-nine".
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