Base | Representation |
---|---|
bin | 10011100110101010111… |
… | …001100110100101000001 |
3 | 11202210100010101222002121 |
4 | 103212222321212211001 |
5 | 134033022122144333 |
6 | 2510520315444241 |
7 | 166221446656651 |
oct | 23465271464501 |
9 | 4683303358077 |
10 | 1347191990593 |
11 | 47a382837209 |
12 | 199117a56681 |
13 | 9a069194427 |
14 | 492c0dac361 |
15 | 2509beec32d |
hex | 139aae66941 |
1347191990593 has 2 divisors, whose sum is σ = 1347191990594. Its totient is φ = 1347191990592.
The previous prime is 1347191990569. The next prime is 1347191990597. The reversal of 1347191990593 is 3950991917431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 849951237184 + 497240753409 = 921928^2 + 705153^2 .
It is a cyclic number.
It is not a de Polignac number, because 1347191990593 - 237 = 1209753037121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1347191990597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 673595995296 + 673595995297.
It is an arithmetic number, because the mean of its divisors is an integer number (673595995297).
Almost surely, 21347191990593 is an apocalyptic number.
It is an amenable number.
1347191990593 is a deficient number, since it is larger than the sum of its proper divisors (1).
1347191990593 is an equidigital number, since it uses as much as digits as its factorization.
1347191990593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8266860, while the sum is 61.
The spelling of 1347191990593 in words is "one trillion, three hundred forty-seven billion, one hundred ninety-one million, nine hundred ninety thousand, five hundred ninety-three".
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