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134721325481 = 221360877237
BaseRepresentation
bin111110101111000000…
…1000100100110101001
3110212201221221102121112
41331132001010212221
54201402124403411
6141520133320105
712506343241451
oct1753601044651
9425657842545
10134721325481
1152153748916
1222139a96035
13c920091152
146740548d61
1537875beb8b
hex1f5e0449a9

134721325481 has 4 divisors (see below), whose sum is σ = 134782204932. Its totient is φ = 134660446032.

The previous prime is 134721325469. The next prime is 134721325499. The reversal of 134721325481 is 184523127431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131412775081 + 3308550400 = 362509^2 + 57520^2 .

It is a cyclic number.

It is not a de Polignac number, because 134721325481 - 210 = 134721324457 is a prime.

It is a super-2 number, since 2×1347213254812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134721325181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30436406 + ... + 30440831.

It is an arithmetic number, because the mean of its divisors is an integer number (33695551233).

Almost surely, 2134721325481 is an apocalyptic number.

It is an amenable number.

134721325481 is a deficient number, since it is larger than the sum of its proper divisors (60879451).

134721325481 is an equidigital number, since it uses as much as digits as its factorization.

134721325481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60879450.

The product of its digits is 161280, while the sum is 41.

The spelling of 134721325481 in words is "one hundred thirty-four billion, seven hundred twenty-one million, three hundred twenty-five thousand, four hundred eighty-one".

Divisors: 1 2213 60877237 134721325481