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134724913801 is a prime number
BaseRepresentation
bin111110101111000111…
…0110000101010001001
3110212202012200201212021
41331132032300222021
54201404034220201
6141520342244441
712506415605152
oct1753616605211
9425665621767
10134724913801
1152155779875
122213b126721
13c920a4950a
146740c00929
153787a7cea1
hex1f5e3b0a89

134724913801 has 2 divisors, whose sum is σ = 134724913802. Its totient is φ = 134724913800.

The previous prime is 134724913753. The next prime is 134724913913. The reversal of 134724913801 is 108319427431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89844067600 + 44880846201 = 299740^2 + 211851^2 .

It is an emirp because it is prime and its reverse (108319427431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134724913801 is a prime.

It is not a weakly prime, because it can be changed into another prime (134724914801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67362456900 + 67362456901.

It is an arithmetic number, because the mean of its divisors is an integer number (67362456901).

Almost surely, 2134724913801 is an apocalyptic number.

It is an amenable number.

134724913801 is a deficient number, since it is larger than the sum of its proper divisors (1).

134724913801 is an equidigital number, since it uses as much as digits as its factorization.

134724913801 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 43.

The spelling of 134724913801 in words is "one hundred thirty-four billion, seven hundred twenty-four million, nine hundred thirteen thousand, eight hundred one".