Base | Representation |
---|---|
bin | 1100010000101110011011… |
… | …1010000001111001101011 |
3 | 1202201211001121121011212122 |
4 | 3010023212322001321223 |
5 | 3231340033211043132 |
6 | 44401150152501455 |
7 | 2561001450462065 |
oct | 304134672017153 |
9 | 52654047534778 |
10 | 13481481346667 |
11 | 4328511838914 |
12 | 16189749aa88b |
13 | 76a3b52bc349 |
14 | 3487159ac735 |
15 | 185a3e611912 |
hex | c42e6e81e6b |
13481481346667 has 2 divisors, whose sum is σ = 13481481346668. Its totient is φ = 13481481346666.
The previous prime is 13481481346649. The next prime is 13481481346673. The reversal of 13481481346667 is 76664318418431.
13481481346667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13481481346667 - 210 = 13481481345643 is a prime.
It is not a weakly prime, because it can be changed into another prime (13481481346967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6740740673333 + 6740740673334.
It is an arithmetic number, because the mean of its divisors is an integer number (6740740673334).
Almost surely, 213481481346667 is an apocalyptic number.
13481481346667 is a deficient number, since it is larger than the sum of its proper divisors (1).
13481481346667 is an equidigital number, since it uses as much as digits as its factorization.
13481481346667 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55738368, while the sum is 62.
The spelling of 13481481346667 in words is "thirteen trillion, four hundred eighty-one billion, four hundred eighty-one million, three hundred forty-six thousand, six hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •