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1348231513361 is a prime number
BaseRepresentation
bin10011100111101000110…
…111000100010100010001
311202220000120110012020212
4103213220313010110101
5134042134231411421
62511211412213505
7166256301530405
oct23475067042421
94686016405225
101348231513361
1147a8665a5037
1219936800a295
139a1a365bb65
144937d087105
152510d3d8e5b
hex139e8dc4511

1348231513361 has 2 divisors, whose sum is σ = 1348231513362. Its totient is φ = 1348231513360.

The previous prime is 1348231513357. The next prime is 1348231513417. The reversal of 1348231513361 is 1633151328431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1241486208400 + 106745304961 = 1114220^2 + 326719^2 .

It is a cyclic number.

It is not a de Polignac number, because 1348231513361 - 22 = 1348231513357 is a prime.

It is not a weakly prime, because it can be changed into another prime (1348231533361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674115756680 + 674115756681.

It is an arithmetic number, because the mean of its divisors is an integer number (674115756681).

Almost surely, 21348231513361 is an apocalyptic number.

It is an amenable number.

1348231513361 is a deficient number, since it is larger than the sum of its proper divisors (1).

1348231513361 is an equidigital number, since it uses as much as digits as its factorization.

1348231513361 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 41.

The spelling of 1348231513361 in words is "one trillion, three hundred forty-eight billion, two hundred thirty-one million, five hundred thirteen thousand, three hundred sixty-one".