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1348397052614 = 219913043259751
BaseRepresentation
bin10011100111110010101…
…110100011001011000110
311202220110002221110102022
4103213302232203023012
5134043004121140424
62511240044243142
7166263351560213
oct23476256431306
94686402843368
101348397052614
1147a940a90137
121993b35404b2
139a1cba3b991
1449397058b0a
152511cbd795e
hex139f2ba32c6

1348397052614 has 16 divisors (see below), whose sum is σ = 2032923052800. Its totient is φ = 670756581000.

The previous prime is 1348397052599. The next prime is 1348397052617. The reversal of 1348397052614 is 4162507938431.

It is a super-2 number, since 2×13483970526142 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1348397052617) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5061239 + ... + 5320989.

It is an arithmetic number, because the mean of its divisors is an integer number (127057690800).

It is a 1-persistent number, because it is pandigital, but 2⋅1348397052614 = 2696794105228 is not.

Almost surely, 21348397052614 is an apocalyptic number.

1348397052614 is a deficient number, since it is larger than the sum of its proper divisors (684526000186).

1348397052614 is a wasteful number, since it uses less digits than its factorization.

1348397052614 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 272995.

The product of its (nonzero) digits is 4354560, while the sum is 53.

The spelling of 1348397052614 in words is "one trillion, three hundred forty-eight billion, three hundred ninety-seven million, fifty-two thousand, six hundred fourteen".

Divisors: 1 2 199 398 13043 26086 259751 519502 2595557 5191114 51690449 103380898 3387932293 6775864586 674198526307 1348397052614