Base | Representation |
---|---|
bin | 10011100111110111000… |
… | …000001011111000010011 |
3 | 11202220122002220211021201 |
4 | 103213313000023320103 |
5 | 134043131002102114 |
6 | 2511251125532031 |
7 | 166265212356433 |
oct | 23476700137023 |
9 | 4686562824251 |
10 | 1348468784659 |
11 | 47a978524517 |
12 | 199413574017 |
13 | 9a210865989 |
14 | 493a27ac2c3 |
15 | 25124156874 |
hex | 139f700be13 |
1348468784659 has 2 divisors, whose sum is σ = 1348468784660. Its totient is φ = 1348468784658.
The previous prime is 1348468784623. The next prime is 1348468784683. The reversal of 1348468784659 is 9564878648431.
It is a strong prime.
It is an emirp because it is prime and its reverse (9564878648431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1348468784659 - 213 = 1348468776467 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1348468784591 and 1348468784600.
It is not a weakly prime, because it can be changed into another prime (1348468784699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674234392329 + 674234392330.
It is an arithmetic number, because the mean of its divisors is an integer number (674234392330).
Almost surely, 21348468784659 is an apocalyptic number.
1348468784659 is a deficient number, since it is larger than the sum of its proper divisors (1).
1348468784659 is an equidigital number, since it uses as much as digits as its factorization.
1348468784659 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1114767360, while the sum is 73.
The spelling of 1348468784659 in words is "one trillion, three hundred forty-eight billion, four hundred sixty-eight million, seven hundred eighty-four thousand, six hundred fifty-nine".
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