Base | Representation |
---|---|
bin | 11001001000101100… |
… | …10110011111001011 |
3 | 1021211110201212102222 |
4 | 30210112112133023 |
5 | 210114123202224 |
6 | 10111023044255 |
7 | 655261256021 |
oct | 144426263713 |
9 | 37743655388 |
10 | 13494740939 |
11 | 57a547a669 |
12 | 274744068b |
13 | 1370a35114 |
14 | 920352711 |
15 | 53eacbb5e |
hex | 3245967cb |
13494740939 has 2 divisors, whose sum is σ = 13494740940. Its totient is φ = 13494740938.
The previous prime is 13494740929. The next prime is 13494740971. The reversal of 13494740939 is 93904749431.
It is a weak prime.
It is an emirp because it is prime and its reverse (93904749431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13494740939 - 28 = 13494740683 is a prime.
It is not a weakly prime, because it can be changed into another prime (13494740929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747370469 + 6747370470.
It is an arithmetic number, because the mean of its divisors is an integer number (6747370470).
Almost surely, 213494740939 is an apocalyptic number.
13494740939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13494740939 is an equidigital number, since it uses as much as digits as its factorization.
13494740939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328, while the sum is 53.
The spelling of 13494740939 in words is "thirteen billion, four hundred ninety-four million, seven hundred forty thousand, nine hundred thirty-nine".
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