Base | Representation |
---|---|
bin | 111110110101101111… |
… | …1111010000000100001 |
3 | 110220022201112220200002 |
4 | 1331223133322000201 |
5 | 4202333030343403 |
6 | 141554413305345 |
7 | 12515060633423 |
oct | 1755337720041 |
9 | 426281486602 |
10 | 134947512353 |
11 | 5225a397415 |
12 | 221a1795255 |
13 | c957bb6934 |
14 | 67625c6813 |
15 | 379c39d188 |
hex | 1f6b7fa021 |
134947512353 has 2 divisors, whose sum is σ = 134947512354. Its totient is φ = 134947512352.
The previous prime is 134947512263. The next prime is 134947512367. The reversal of 134947512353 is 353215749431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134947491904 + 20449 = 367352^2 + 143^2 .
It is a cyclic number.
It is not a de Polignac number, because 134947512353 - 28 = 134947512097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134947512298 and 134947512307.
It is not a weakly prime, because it can be changed into another prime (134947512253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67473756176 + 67473756177.
It is an arithmetic number, because the mean of its divisors is an integer number (67473756177).
Almost surely, 2134947512353 is an apocalyptic number.
It is an amenable number.
134947512353 is a deficient number, since it is larger than the sum of its proper divisors (1).
134947512353 is an equidigital number, since it uses as much as digits as its factorization.
134947512353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1360800, while the sum is 47.
The spelling of 134947512353 in words is "one hundred thirty-four billion, nine hundred forty-seven million, five hundred twelve thousand, three hundred fifty-three".
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