1349498483 has 2 divisors, whose sum is σ = 1349498484. Its totient is φ = 1349498482.

The previous prime is 1349498473. The next prime is 1349498489. The reversal of 1349498483 is 3848949431.

It is a strong prime.

It is an emirp because it is prime and its reverse (3848949431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1349498483 - 2¹⁰ = 1349497459 is a prime.

It is a super-3 number, since 3×1349498483³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1349498489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674749241 + 674749242.

It is an arithmetic number, because the mean of its divisors is an integer number (674749242).

Almost surely, 2^1349498483 is an apocalyptic number.

1349498483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349498483 is an equidigital number, since it uses as much as digits as its factorization.

1349498483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2985984, while the sum is 53.

The square root of 1349498483 is about 36735.5207258588. The cubic root of 1349498483 is about 1105.0725730541.

The spelling of 1349498483 in words is "one billion, three hundred forty-nine million, four hundred ninety-eight thousand, four hundred eighty-three".