Base | Representation |
---|---|
bin | 111110110110010101… |
… | …1101011110010111001 |
3 | 110220101002221010221202 |
4 | 1331230223223302321 |
5 | 4202403122031311 |
6 | 142000403143545 |
7 | 12515421530165 |
oct | 1755453536271 |
9 | 426332833852 |
10 | 134967377081 |
11 | 5226a625049 |
12 | 221a8374bb5 |
13 | c95c050604 |
14 | 67650b7ca5 |
15 | 379dec3e3b |
hex | 1f6caebcb9 |
134967377081 has 2 divisors, whose sum is σ = 134967377082. Its totient is φ = 134967377080.
The previous prime is 134967377029. The next prime is 134967377089. The reversal of 134967377081 is 180773769431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132230413225 + 2736963856 = 363635^2 + 52316^2 .
It is a cyclic number.
It is not a de Polignac number, because 134967377081 - 218 = 134967114937 is a prime.
It is a super-2 number, since 2×1349673770812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134967377089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67483688540 + 67483688541.
It is an arithmetic number, because the mean of its divisors is an integer number (67483688541).
Almost surely, 2134967377081 is an apocalyptic number.
It is an amenable number.
134967377081 is a deficient number, since it is larger than the sum of its proper divisors (1).
134967377081 is an equidigital number, since it uses as much as digits as its factorization.
134967377081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5334336, while the sum is 56.
The spelling of 134967377081 in words is "one hundred thirty-four billion, nine hundred sixty-seven million, three hundred seventy-seven thousand, eighty-one".
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