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134968580561 is a prime number
BaseRepresentation
bin111110110110011000…
…0010001100111010001
3110220101012012021211002
41331230300101213101
54202403424034221
6142000445031345
712515435001653
oct1755460214721
9426335167732
10134968580561
1152270277261
12221a8855555
13c95c382329
14676530c6d3
15379e16080b
hex1f6cc119d1

134968580561 has 2 divisors, whose sum is σ = 134968580562. Its totient is φ = 134968580560.

The previous prime is 134968580491. The next prime is 134968580597. The reversal of 134968580561 is 165085869431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132673691536 + 2294889025 = 364244^2 + 47905^2 .

It is a cyclic number.

It is not a de Polignac number, because 134968580561 - 214 = 134968564177 is a prime.

It is a super-2 number, since 2×1349685805612 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134968580497 and 134968580506.

It is not a weakly prime, because it can be changed into another prime (134968588561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67484290280 + 67484290281.

It is an arithmetic number, because the mean of its divisors is an integer number (67484290281).

Almost surely, 2134968580561 is an apocalyptic number.

It is an amenable number.

134968580561 is a deficient number, since it is larger than the sum of its proper divisors (1).

134968580561 is an equidigital number, since it uses as much as digits as its factorization.

134968580561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6220800, while the sum is 56.

The spelling of 134968580561 in words is "one hundred thirty-four billion, nine hundred sixty-eight million, five hundred eighty thousand, five hundred sixty-one".