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13497139 = 53254663
BaseRepresentation
bin110011011111…
…001100110011
3221101201121001
4303133030303
511423402024
61201142431
7222503155
oct63371463
927351531
1013497139
117689667
12462aa17
132a47596
141b14ad5
1512b9244
hexcdf333

13497139 has 4 divisors (see below), whose sum is σ = 13751856. Its totient is φ = 13242424.

The previous prime is 13497109. The next prime is 13497149. The reversal of 13497139 is 93179431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13497139 is a prime.

It is a super-2 number, since 2×134971392 = 364345522370642, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13497098 and 13497107.

It is not an unprimeable number, because it can be changed into a prime (13497109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127279 + ... + 127384.

It is an arithmetic number, because the mean of its divisors is an integer number (3437964).

Almost surely, 213497139 is an apocalyptic number.

13497139 is a deficient number, since it is larger than the sum of its proper divisors (254717).

13497139 is an equidigital number, since it uses as much as digits as its factorization.

13497139 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254716.

The product of its digits is 20412, while the sum is 37.

The square root of 13497139 is about 3673.8452607588. The cubic root of 13497139 is about 238.0933360350.

The spelling of 13497139 in words is "thirteen million, four hundred ninety-seven thousand, one hundred thirty-nine".

Divisors: 1 53 254663 13497139