1350011601001 has 4 divisors (see below), whose sum is σ = 1542870401152. Its totient is φ = 1157152800852.

The previous prime is 1350011600957. The next prime is 1350011601031. The reversal of 1350011601001 is 1001061100531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1350011601001 - 2²¹ = 1350009503849 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1350011601001.

It is not an unprimeable number, because it can be changed into a prime (1350011601031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96429400065 + ... + 96429400078.

It is an arithmetic number, because the mean of its divisors is an integer number (385717600288).

Almost surely, 2^{1350011601001} is an apocalyptic number.

It is an amenable number.

1350011601001 is a deficient number, since it is larger than the sum of its proper divisors (192858800151).

1350011601001 is an equidigital number, since it uses as much as digits as its factorization.

1350011601001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 192858800150.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 1350011601001 its reverse (1001061100531), we get a palindrome (2351072701532).

The spelling of 1350011601001 in words is "one trillion, three hundred fifty billion, eleven million, six hundred one thousand, one".