Base | Representation |
---|---|
bin | 111110110111010110… |
… | …0101110011000010011 |
3 | 110220110110120202002121 |
4 | 1331232230232120103 |
5 | 4202440302013433 |
6 | 142004012155111 |
7 | 12516312205513 |
oct | 1755654563023 |
9 | 426413522077 |
10 | 135001204243 |
11 | 52287729984 |
12 | 221b7768a97 |
13 | c966065599 |
14 | 67697a1843 |
15 | 37a1e56c2d |
hex | 1f6eb2e613 |
135001204243 has 4 divisors (see below), whose sum is σ = 135134473968. Its totient is φ = 134867934520.
The previous prime is 135001204229. The next prime is 135001204277. The reversal of 135001204243 is 342402100531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 342402100531 = 3547 ⋅96532873.
It is a cyclic number.
It is not a de Polignac number, because 135001204243 - 29 = 135001203731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135001204543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66633343 + ... + 66635368.
It is an arithmetic number, because the mean of its divisors is an integer number (33783618492).
Almost surely, 2135001204243 is an apocalyptic number.
135001204243 is a deficient number, since it is larger than the sum of its proper divisors (133269725).
135001204243 is a wasteful number, since it uses less digits than its factorization.
135001204243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133269724.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 135001204243 its reverse (342402100531), we get a palindrome (477403304774).
The spelling of 135001204243 in words is "one hundred thirty-five billion, one million, two hundred four thousand, two hundred forty-three".
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