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1350020227 is a prime number
BaseRepresentation
bin101000001110111…
…1010110010000011
310111002022010121011
41100131322302003
510231101121402
6341543341351
745311661013
oct12035726203
93432263534
101350020227
116330621a6
12318151857
131868cc64a
14cb421c43
157d7c0ed7
hex5077ac83

1350020227 has 2 divisors, whose sum is σ = 1350020228. Its totient is φ = 1350020226.

The previous prime is 1350020207. The next prime is 1350020233. The reversal of 1350020227 is 7220200531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350020227 is a prime.

It is a super-2 number, since 2×13500202272 = 3645109226618263058, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1350020198 and 1350020207.

It is not a weakly prime, because it can be changed into another prime (1350020207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675010113 + 675010114.

It is an arithmetic number, because the mean of its divisors is an integer number (675010114).

Almost surely, 21350020227 is an apocalyptic number.

1350020227 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350020227 is an equidigital number, since it uses as much as digits as its factorization.

1350020227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 22.

The square root of 1350020227 is about 36742.6213953224. The cubic root of 1350020227 is about 1105.2149693353.

Adding to 1350020227 its reverse (7220200531), we get a palindrome (8570220758).

The spelling of 1350020227 in words is "one billion, three hundred fifty million, twenty thousand, two hundred twenty-seven".