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13500303210052 = 223375075802513
BaseRepresentation
bin1100010001110100100011…
…0001101111011001000100
31202210121122100020220111221
43010131020301233121010
53232142110110210202
644413541554410124
72562236045620261
oct304351061573104
952717570226457
1013500303210052
1143354a023440a
121620548290944
1376c0c4889109
143495bd616268
15186291c10037
hexc4748c6f644

13500303210052 has 6 divisors (see below), whose sum is σ = 23625530617598. Its totient is φ = 6750151605024.

The previous prime is 13500303210041. The next prime is 13500303210127. The reversal of 13500303210052 is 25001230300531.

It can be written as a sum of positive squares in only one way, i.e., 12398525491716 + 1101777718336 = 3521154^2 + 1049656^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13500303209999 and 13500303210026.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1687537901253 + ... + 1687537901260.

Almost surely, 213500303210052 is an apocalyptic number.

It is an amenable number.

13500303210052 is a deficient number, since it is larger than the sum of its proper divisors (10125227407546).

13500303210052 is a wasteful number, since it uses less digits than its factorization.

13500303210052 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3375075802517 (or 3375075802515 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 13500303210052 its reverse (25001230300531), we get a palindrome (38501533510583).

The spelling of 13500303210052 in words is "thirteen trillion, five hundred billion, three hundred three million, two hundred ten thousand, fifty-two".

Divisors: 1 2 4 3375075802513 6750151605026 13500303210052