Base | Representation |
---|---|
bin | 111110110111011110… |
… | …1010011110111110001 |
3 | 110220110202202122020211 |
4 | 1331232331103313301 |
5 | 4202442410131423 |
6 | 142004245304121 |
7 | 12516364154515 |
oct | 1755675236761 |
9 | 426422678224 |
10 | 135005552113 |
11 | 5228a129563 |
12 | 221b9105041 |
13 | c966c285a3 |
14 | 676a1b4145 |
15 | 37a251510d |
hex | 1f6ef53df1 |
135005552113 has 2 divisors, whose sum is σ = 135005552114. Its totient is φ = 135005552112.
The previous prime is 135005552021. The next prime is 135005552137. The reversal of 135005552113 is 311255500531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71255361969 + 63750190144 = 266937^2 + 252488^2 .
It is a cyclic number.
It is not a de Polignac number, because 135005552113 - 233 = 126415617521 is a prime.
It is not a weakly prime, because it can be changed into another prime (135005552183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67502776056 + 67502776057.
It is an arithmetic number, because the mean of its divisors is an integer number (67502776057).
Almost surely, 2135005552113 is an apocalyptic number.
It is an amenable number.
135005552113 is a deficient number, since it is larger than the sum of its proper divisors (1).
135005552113 is an equidigital number, since it uses as much as digits as its factorization.
135005552113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 135005552113 in words is "one hundred thirty-five billion, five million, five hundred fifty-two thousand, one hundred thirteen".
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