135006443451353 has 2 divisors, whose sum is σ = 135006443451354. Its totient is φ = 135006443451352.

The previous prime is 135006443451349. The next prime is 135006443451427. The reversal of 135006443451353 is 353154344600531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121192532527504 + 13813910923849 = 11008748^2 + 3716707^2 .

It is a cyclic number.

It is not a de Polignac number, because 135006443451353 - 2² = 135006443451349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135006443451298 and 135006443451307.

It is not a weakly prime, because it can be changed into another prime (135006443451343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67503221725676 + 67503221725677.

It is an arithmetic number, because the mean of its divisors is an integer number (67503221725677).

Almost surely, 2^{135006443451353} is an apocalyptic number.

It is an amenable number.

135006443451353 is a deficient number, since it is larger than the sum of its proper divisors (1).

135006443451353 is an equidigital number, since it uses as much as digits as its factorization.

135006443451353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888000, while the sum is 47.

The spelling of 135006443451353 in words is "one hundred thirty-five trillion, six billion, four hundred forty-three million, four hundred fifty-one thousand, three hundred fifty-three".