Base | Representation |
---|---|
bin | 1100010001111000010001… |
… | …1001100011100111100011 |
3 | 1202210201020001111001221011 |
4 | 3010132010121203213203 |
5 | 3232201132144101311 |
6 | 44414225130241351 |
7 | 2562302613152230 |
oct | 304360431434743 |
9 | 52721201431834 |
10 | 13501303503331 |
11 | 4335963938576 |
12 | 1620787286257 |
13 | 76c223b99927 |
14 | 3496763dc787 |
15 | 1862ee94d321 |
hex | c47846639e3 |
13501303503331 has 16 divisors (see below), whose sum is σ = 16105583453184. Its totient is φ = 11066194760544.
The previous prime is 13501303503323. The next prime is 13501303503343. The reversal of 13501303503331 is 13330530310531.
It is not a de Polignac number, because 13501303503331 - 23 = 13501303503323 is a prime.
It is a super-2 number, since 2×135013035033312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13501303503293 and 13501303503302.
It is not an unprimeable number, because it can be changed into a prime (13501303503371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11550316 + ... + 12665401.
It is an arithmetic number, because the mean of its divisors is an integer number (1006598965824).
Almost surely, 213501303503331 is an apocalyptic number.
13501303503331 is a deficient number, since it is larger than the sum of its proper divisors (2604279949853).
13501303503331 is a wasteful number, since it uses less digits than its factorization.
13501303503331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24219210.
The product of its (nonzero) digits is 18225, while the sum is 31.
Adding to 13501303503331 its reverse (13330530310531), we get a palindrome (26831833813862).
The spelling of 13501303503331 in words is "thirteen trillion, five hundred one billion, three hundred three million, five hundred three thousand, three hundred thirty-one".
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