13501960793 has 4 divisors (see below), whose sum is σ = 13605029328. Its totient is φ = 13398892260.

The previous prime is 13501960777. The next prime is 13501960799. The reversal of 13501960793 is 39706910531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39706910531 = 71 ⋅559252261.

It is a cyclic number.

It is not a de Polignac number, because 13501960793 - 2⁴ = 13501960777 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13501960799) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51534071 + ... + 51534332.

It is an arithmetic number, because the mean of its divisors is an integer number (3401257332).

Almost surely, 2^13501960793 is an apocalyptic number.

It is an amenable number.

13501960793 is a deficient number, since it is larger than the sum of its proper divisors (103068535).

13501960793 is a wasteful number, since it uses less digits than its factorization.

13501960793 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103068534.

The product of its (nonzero) digits is 153090, while the sum is 44.

The spelling of 13501960793 in words is "thirteen billion, five hundred one million, nine hundred sixty thousand, seven hundred ninety-three".