Base | Representation |
---|---|
bin | 1100010001111010111000… |
… | …0100001110101000101010 |
3 | 1202210210000202212121010210 |
4 | 3010132232010032220222 |
5 | 3232204100123233214 |
6 | 44414422341321550 |
7 | 2562326132045061 |
oct | 304365604165052 |
9 | 52723022777123 |
10 | 13502002555434 |
11 | 433619249a788 |
12 | 16209414062b6 |
13 | 76c305966723 |
14 | 3497011ab1d8 |
15 | 186340ed4b59 |
hex | c47ae10ea2a |
13502002555434 has 32 divisors (see below), whose sum is σ = 27096383321280. Its totient is φ = 4485283229952.
The previous prime is 13502002555397. The next prime is 13502002555477. The reversal of 13502002555434 is 43455520020531.
It is a junction number, because it is equal to n+sod(n) for n = 13502002555392 and 13502002555401.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2965977 + ... + 5983395.
It is an arithmetic number, because the mean of its divisors is an integer number (846761978790).
Almost surely, 213502002555434 is an apocalyptic number.
13502002555434 is an abundant number, since it is smaller than the sum of its proper divisors (13594380765846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13502002555434 is a wasteful number, since it uses less digits than its factorization.
13502002555434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3019974.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 13502002555434 its reverse (43455520020531), we get a palindrome (56957522575965).
The spelling of 13502002555434 in words is "thirteen trillion, five hundred two billion, two million, five hundred fifty-five thousand, four hundred thirty-four".
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