Base | Representation |
---|---|
bin | 111110110111111010… |
… | …0111101011001110011 |
3 | 110220111210012210021101 |
4 | 1331233310331121303 |
5 | 4203010123441042 |
6 | 142005530105231 |
7 | 12516632153314 |
oct | 1755764753163 |
9 | 426453183241 |
10 | 135020140147 |
11 | 52297392792 |
12 | 22201b7b217 |
13 | c969c65569 |
14 | 676c0d060b |
15 | 37a39476b7 |
hex | 1f6fd3d673 |
135020140147 has 2 divisors, whose sum is σ = 135020140148. Its totient is φ = 135020140146.
The previous prime is 135020140081. The next prime is 135020140169. The reversal of 135020140147 is 741041020531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135020140147 is a prime.
It is not a weakly prime, because it can be changed into another prime (135020840147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67510070073 + 67510070074.
It is an arithmetic number, because the mean of its divisors is an integer number (67510070074).
Almost surely, 2135020140147 is an apocalyptic number.
135020140147 is a deficient number, since it is larger than the sum of its proper divisors (1).
135020140147 is an equidigital number, since it uses as much as digits as its factorization.
135020140147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 135020140147 its reverse (741041020531), we get a palindrome (876061160678).
The spelling of 135020140147 in words is "one hundred thirty-five billion, twenty million, one hundred forty thousand, one hundred forty-seven".
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