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135020140147 is a prime number
BaseRepresentation
bin111110110111111010…
…0111101011001110011
3110220111210012210021101
41331233310331121303
54203010123441042
6142005530105231
712516632153314
oct1755764753163
9426453183241
10135020140147
1152297392792
1222201b7b217
13c969c65569
14676c0d060b
1537a39476b7
hex1f6fd3d673

135020140147 has 2 divisors, whose sum is σ = 135020140148. Its totient is φ = 135020140146.

The previous prime is 135020140081. The next prime is 135020140169. The reversal of 135020140147 is 741041020531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135020140147 is a prime.

It is not a weakly prime, because it can be changed into another prime (135020840147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67510070073 + 67510070074.

It is an arithmetic number, because the mean of its divisors is an integer number (67510070074).

Almost surely, 2135020140147 is an apocalyptic number.

135020140147 is a deficient number, since it is larger than the sum of its proper divisors (1).

135020140147 is an equidigital number, since it uses as much as digits as its factorization.

135020140147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 28.

Adding to 135020140147 its reverse (741041020531), we get a palindrome (876061160678).

The spelling of 135020140147 in words is "one hundred thirty-five billion, twenty million, one hundred forty thousand, one hundred forty-seven".