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1350244345442 = 2675122172721
BaseRepresentation
bin10011101001100000110…
…101011010011001100010
311210002012211221122210012
4103221200311122121202
5134110300023023232
62512143234204522
7166360212365456
oct23514065323142
94702184848705
101350244345442
114806a9806623
1219982a123742
139a434679b65
14494d0522666
15251c9e839b2
hex13a60d5a662

1350244345442 has 4 divisors (see below), whose sum is σ = 2025366518166. Its totient is φ = 675122172720.

The previous prime is 1350244345441. The next prime is 1350244345451. The reversal of 1350244345442 is 2445434420531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1315473657481 + 34770687961 = 1146941^2 + 186469^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1350244345442.

It is not an unprimeable number, because it can be changed into a prime (1350244345441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337561086359 + ... + 337561086362.

Almost surely, 21350244345442 is an apocalyptic number.

1350244345442 is a deficient number, since it is larger than the sum of its proper divisors (675122172724).

1350244345442 is an equidigital number, since it uses as much as digits as its factorization.

1350244345442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 675122172723.

The product of its (nonzero) digits is 921600, while the sum is 41.

Adding to 1350244345442 its reverse (2445434420531), we get a palindrome (3795678765973).

The spelling of 1350244345442 in words is "one trillion, three hundred fifty billion, two hundred forty-four million, three hundred forty-five thousand, four hundred forty-two".

Divisors: 1 2 675122172721 1350244345442