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1350250116122 = 2675125058061
BaseRepresentation
bin10011101001100001001…
…011011011010000011010
311210002020020210211200002
4103221201023123100122
5134110303012203442
62512144002013002
7166360312421555
oct23514113332032
94702206724602
101350250116122
11480701a98186
12199830047162
139a43591a66b
14494d11c569c
15251ca723732
hex13a612db41a

1350250116122 has 4 divisors (see below), whose sum is σ = 2025375174186. Its totient is φ = 675125058060.

The previous prime is 1350250116121. The next prime is 1350250116139. The reversal of 1350250116122 is 2216110520531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1349637504121 + 612612001 = 1161739^2 + 24751^2 .

It is a super-3 number, since 3×13502501161223 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1350250116121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337562529029 + ... + 337562529032.

Almost surely, 21350250116122 is an apocalyptic number.

1350250116122 is a deficient number, since it is larger than the sum of its proper divisors (675125058064).

1350250116122 is an equidigital number, since it uses as much as digits as its factorization.

1350250116122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 675125058063.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 1350250116122 its reverse (2216110520531), we get a palindrome (3566360636653).

The spelling of 1350250116122 in words is "one trillion, three hundred fifty billion, two hundred fifty million, one hundred sixteen thousand, one hundred twenty-two".

Divisors: 1 2 675125058061 1350250116122