Base | Representation |
---|---|
bin | 10011101001100001001… |
… | …011011011010000011010 |
3 | 11210002020020210211200002 |
4 | 103221201023123100122 |
5 | 134110303012203442 |
6 | 2512144002013002 |
7 | 166360312421555 |
oct | 23514113332032 |
9 | 4702206724602 |
10 | 1350250116122 |
11 | 480701a98186 |
12 | 199830047162 |
13 | 9a43591a66b |
14 | 494d11c569c |
15 | 251ca723732 |
hex | 13a612db41a |
1350250116122 has 4 divisors (see below), whose sum is σ = 2025375174186. Its totient is φ = 675125058060.
The previous prime is 1350250116121. The next prime is 1350250116139. The reversal of 1350250116122 is 2216110520531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1349637504121 + 612612001 = 1161739^2 + 24751^2 .
It is a super-3 number, since 3×13502501161223 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1350250116121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337562529029 + ... + 337562529032.
Almost surely, 21350250116122 is an apocalyptic number.
1350250116122 is a deficient number, since it is larger than the sum of its proper divisors (675125058064).
1350250116122 is an equidigital number, since it uses as much as digits as its factorization.
1350250116122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 675125058063.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1350250116122 its reverse (2216110520531), we get a palindrome (3566360636653).
The spelling of 1350250116122 in words is "one trillion, three hundred fifty billion, two hundred fifty million, one hundred sixteen thousand, one hundred twenty-two".
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