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1350256015193 is a prime number
BaseRepresentation
bin10011101001100001100…
…001111011011101011001
311210002020122220112200012
4103221201201323131121
5134110311014441233
62512144332251305
7166360413521201
oct23514141733531
94702218815605
101350256015193
11480705357248
12199832010b35
139a436c04737
14494d1cbd401
15251caedb548
hex13a6187b759

1350256015193 has 2 divisors, whose sum is σ = 1350256015194. Its totient is φ = 1350256015192.

The previous prime is 1350256015169. The next prime is 1350256015223. The reversal of 1350256015193 is 3915106520531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 700856957584 + 649399057609 = 837172^2 + 805853^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350256015193 - 210 = 1350256014169 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1350256015193.

It is not a weakly prime, because it can be changed into another prime (1350256015103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675128007596 + 675128007597.

It is an arithmetic number, because the mean of its divisors is an integer number (675128007597).

Almost surely, 21350256015193 is an apocalyptic number.

It is an amenable number.

1350256015193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350256015193 is an equidigital number, since it uses as much as digits as its factorization.

1350256015193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 121500, while the sum is 41.

The spelling of 1350256015193 in words is "one trillion, three hundred fifty billion, two hundred fifty-six million, fifteen thousand, one hundred ninety-three".