1350300121 has 2 divisors, whose sum is σ = 1350300122. Its totient is φ = 1350300120.

The previous prime is 1350300097. The next prime is 1350300143. The reversal of 1350300121 is 1210030531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 710968896 + 639331225 = 26664^2 + 25285^2 .

It is an emirp because it is prime and its reverse (1210030531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1350300121 - 2⁹ = 1350299609 is a prime.

It is a super-2 number, since 2×1350300121² = 3646620833545229282, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1350300095 and 1350300104.

It is not a weakly prime, because it can be changed into another prime (1350304121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675150060 + 675150061.

It is an arithmetic number, because the mean of its divisors is an integer number (675150061).

Almost surely, 2^1350300121 is an apocalyptic number.

It is an amenable number.

1350300121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350300121 is an equidigital number, since it uses as much as digits as its factorization.

1350300121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 1350300121 is about 36746.4300442914. The cubic root of 1350300121 is about 1105.2913439102.

Adding to 1350300121 its reverse (1210030531), we get a palindrome (2560330652).

The spelling of 1350300121 in words is "one billion, three hundred fifty million, three hundred thousand, one hundred twenty-one".