Base | Representation |
---|---|
bin | 10011101001100110001… |
… | …000000010011111100001 |
3 | 11210002110000222120211001 |
4 | 103221212020002133201 |
5 | 134110440234124322 |
6 | 2512200124552001 |
7 | 166362341043064 |
oct | 23514610023741 |
9 | 4702400876731 |
10 | 1350333114337 |
11 | 480744926a49 |
12 | 1998539b2601 |
13 | 9a449b8a62c |
14 | 494dc22c8db |
15 | 251d2b6a827 |
hex | 13a662027e1 |
1350333114337 has 2 divisors, whose sum is σ = 1350333114338. Its totient is φ = 1350333114336.
The previous prime is 1350333114241. The next prime is 1350333114367. The reversal of 1350333114337 is 7334113330531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1263558094561 + 86775019776 = 1124081^2 + 294576^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350333114337 - 239 = 800577300449 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350333114296 and 1350333114305.
It is not a weakly prime, because it can be changed into another prime (1350333114367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675166557168 + 675166557169.
It is an arithmetic number, because the mean of its divisors is an integer number (675166557169).
Almost surely, 21350333114337 is an apocalyptic number.
It is an amenable number.
1350333114337 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350333114337 is an equidigital number, since it uses as much as digits as its factorization.
1350333114337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102060, while the sum is 37.
Adding to 1350333114337 its reverse (7334113330531), we get a palindrome (8684446444868).
The spelling of 1350333114337 in words is "one trillion, three hundred fifty billion, three hundred thirty-three million, one hundred fourteen thousand, three hundred thirty-seven".
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