1350340430531 has 4 divisors (see below), whose sum is σ = 1351050764064. Its totient is φ = 1349630097000.

The previous prime is 1350340430521. The next prime is 1350340430557.

1350340430531 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1350340430531 is a prime.

It is a super-2 number, since 2×1350340430531² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1350340430521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355163915 + ... + 355167716.

It is an arithmetic number, because the mean of its divisors is an integer number (337762691016).

Almost surely, 2^{1350340430531} is an apocalyptic number.

1350340430531 is a deficient number, since it is larger than the sum of its proper divisors (710333533).

1350340430531 is an equidigital number, since it uses as much as digits as its factorization.

1350340430531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710333532.

The product of its (nonzero) digits is 32400, while the sum is 32.

It can be divided in two parts, 1350340 and 430531, that added together give a palindrome (1780871).

The spelling of 1350340430531 in words is "one trillion, three hundred fifty billion, three hundred forty million, four hundred thirty thousand, five hundred thirty-one".