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135038041 is a prime number
BaseRepresentation
bin10000000110010…
…00010001011001
3100102002122100221
420003020101121
5234032204131
621222200041
73226542625
oct1003102131
9312078327
10135038041
116a253096
1239283021
1321c90988
1413d12185
15bcc6411
hex80c8459

135038041 has 2 divisors, whose sum is σ = 135038042. Its totient is φ = 135038040.

The previous prime is 135038027. The next prime is 135038063. The reversal of 135038041 is 140830531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74649600 + 60388441 = 8640^2 + 7771^2 .

It is a cyclic number.

It is not a de Polignac number, because 135038041 - 27 = 135037913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135037997 and 135038015.

It is not a weakly prime, because it can be changed into another prime (135038741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67519020 + 67519021.

It is an arithmetic number, because the mean of its divisors is an integer number (67519021).

Almost surely, 2135038041 is an apocalyptic number.

It is an amenable number.

135038041 is a deficient number, since it is larger than the sum of its proper divisors (1).

135038041 is an equidigital number, since it uses as much as digits as its factorization.

135038041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 135038041 is about 11620.5869473104. The cubic root of 135038041 is about 513.0409640667.

Adding to 135038041 its reverse (140830531), we get a palindrome (275868572).

The spelling of 135038041 in words is "one hundred thirty-five million, thirty-eight thousand, forty-one".