Base | Representation |
---|---|
bin | 1100010010000011001101… |
… | …1011011101100001011010 |
3 | 1202210222210201001100021021 |
4 | 3010200303123131201122 |
5 | 3232223140420443300 |
6 | 44415432350033054 |
7 | 2562435441123112 |
oct | 304406333354132 |
9 | 52728721040237 |
10 | 13504240015450 |
11 | 4337130485598 |
12 | 16212667a878a |
13 | 76c5a1382772 |
14 | 3498743da042 |
15 | 186422650d1a |
hex | c48336dd85a |
13504240015450 has 12 divisors (see below), whose sum is σ = 25117886428830. Its totient is φ = 5401696006160.
The previous prime is 13504240015381. The next prime is 13504240015457. The reversal of 13504240015450 is 5451004240531.
It can be written as a sum of positive squares in 3 ways, for example, as 12615404001489 + 888836013961 = 3551817^2 + 942781^2 .
It is not an unprimeable number, because it can be changed into a prime (13504240015457) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 135042400105 + ... + 135042400204.
Almost surely, 213504240015450 is an apocalyptic number.
13504240015450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13504240015450 is a deficient number, since it is larger than the sum of its proper divisors (11613646413380).
13504240015450 is a wasteful number, since it uses less digits than its factorization.
13504240015450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270084800321 (or 270084800316 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 34.
Adding to 13504240015450 its reverse (5451004240531), we get a palindrome (18955244255981).
The spelling of 13504240015450 in words is "thirteen trillion, five hundred four billion, two hundred forty million, fifteen thousand, four hundred fifty".
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