Base | Representation |
---|---|
bin | 1100010010000011001110… |
… | …1000111000110111101110 |
3 | 1202210222210221200011122122 |
4 | 3010200303220320313232 |
5 | 3232223142321112332 |
6 | 44415432553312542 |
7 | 2562435513053150 |
oct | 304406350706756 |
9 | 52728727604578 |
10 | 13504243535342 |
11 | 433713246a09a |
12 | 1621267a05752 |
13 | 76c5a2015941 |
14 | 349874a74ad0 |
15 | 186422ae8c12 |
hex | c4833a38dee |
13504243535342 has 32 divisors (see below), whose sum is σ = 23188425845760. Its totient is φ = 5777967080160.
The previous prime is 13504243535227. The next prime is 13504243535389. The reversal of 13504243535342 is 24353534240531.
13504243535342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13504243535293 and 13504243535302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20937509 + ... + 21572847.
It is an arithmetic number, because the mean of its divisors is an integer number (724638307680).
Almost surely, 213504243535342 is an apocalyptic number.
13504243535342 is a deficient number, since it is larger than the sum of its proper divisors (9684182310418).
13504243535342 is a wasteful number, since it uses less digits than its factorization.
13504243535342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 637856.
The product of its (nonzero) digits is 2592000, while the sum is 44.
Adding to 13504243535342 its reverse (24353534240531), we get a palindrome (37857777775873).
The spelling of 13504243535342 in words is "thirteen trillion, five hundred four billion, two hundred forty-three million, five hundred thirty-five thousand, three hundred forty-two".
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