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1350426322937 is a prime number
BaseRepresentation
bin10011101001101011101…
…011100110011111111001
311210002200112101001222102
4103221223223212133321
5134111133114313222
62512213254433145
7166364552231216
oct23515353463771
94702615331872
101350426322937
114807924a9a4a
1219987b0627b5
139a463293b53
144950a772b0d
15251dae2cd92
hex13a6bae67f9

1350426322937 has 2 divisors, whose sum is σ = 1350426322938. Its totient is φ = 1350426322936.

The previous prime is 1350426322909. The next prime is 1350426322963. The reversal of 1350426322937 is 7392236240531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1328830257001 + 21596065936 = 1152749^2 + 146956^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350426322937 - 220 = 1350425274361 is a prime.

It is a super-2 number, since 2×13504263229372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1350426322891 and 1350426322900.

It is not a weakly prime, because it can be changed into another prime (1350426324937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675213161468 + 675213161469.

It is an arithmetic number, because the mean of its divisors is an integer number (675213161469).

Almost surely, 21350426322937 is an apocalyptic number.

It is an amenable number.

1350426322937 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350426322937 is an equidigital number, since it uses as much as digits as its factorization.

1350426322937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 47.

The spelling of 1350426322937 in words is "one trillion, three hundred fifty billion, four hundred twenty-six million, three hundred twenty-two thousand, nine hundred thirty-seven".