Base | Representation |
---|---|
bin | 10011101001101011111… |
… | …111100001000010001001 |
3 | 11210002200220012022011010 |
4 | 103221223333201002021 |
5 | 134111140433342213 |
6 | 2512214002354133 |
7 | 166364644503300 |
oct | 23515377410211 |
9 | 4702626168133 |
10 | 1350431543433 |
11 | 480795445205 |
12 | 19988095b949 |
13 | 9a4643a10bb |
14 | 4950b331437 |
15 | 251db60eac3 |
hex | 13a6bfe1089 |
1350431543433 has 24 divisors (see below), whose sum is σ = 2143257286368. Its totient is φ = 753729230016.
The previous prime is 1350431543423. The next prime is 1350431543437. The reversal of 1350431543433 is 3343451340531.
It is not a de Polignac number, because 1350431543433 - 210 = 1350431542409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350431543391 and 1350431543400.
It is not an unprimeable number, because it can be changed into a prime (1350431543437) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 106814716 + ... + 106827357.
It is an arithmetic number, because the mean of its divisors is an integer number (89302386932).
Almost surely, 21350431543433 is an apocalyptic number.
It is an amenable number.
1350431543433 is a deficient number, since it is larger than the sum of its proper divisors (792825742935).
1350431543433 is a wasteful number, since it uses less digits than its factorization.
1350431543433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213642133 (or 213642126 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 1350431543433 its reverse (3343451340531), we get a palindrome (4693882883964).
The spelling of 1350431543433 in words is "one trillion, three hundred fifty billion, four hundred thirty-one million, five hundred forty-three thousand, four hundred thirty-three".
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