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1350453221041 is a prime number
BaseRepresentation
bin10011101001101101010…
…010001101011010110001
311210002202101222122020111
4103221231102031122301
5134111212011033131
62512220055141321
7166365326660311
oct23515522153261
94702671878214
101350453221041
114807a6700991
12199888074841
139a468a20ca2
1449510175441
15251dd492ab1
hex13a6d48d6b1

1350453221041 has 2 divisors, whose sum is σ = 1350453221042. Its totient is φ = 1350453221040.

The previous prime is 1350453221003. The next prime is 1350453221057. The reversal of 1350453221041 is 1401223540531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1149031781041 + 201421440000 = 1071929^2 + 448800^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350453221041 - 223 = 1350444832433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1350453220994 and 1350453221012.

It is not a weakly prime, because it can be changed into another prime (1350453221641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675226610520 + 675226610521.

It is an arithmetic number, because the mean of its divisors is an integer number (675226610521).

Almost surely, 21350453221041 is an apocalyptic number.

It is an amenable number.

1350453221041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350453221041 is an equidigital number, since it uses as much as digits as its factorization.

1350453221041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1350453221041 its reverse (1401223540531), we get a palindrome (2751676761572).

The spelling of 1350453221041 in words is "one trillion, three hundred fifty billion, four hundred fifty-three million, two hundred twenty-one thousand, forty-one".