Base | Representation |
---|---|
bin | 111110111000111001… |
… | …0011101101101101011 |
3 | 110220121002010022001122 |
4 | 1331301302131231223 |
5 | 4203042034243431 |
6 | 142013103205455 |
7 | 12520511621555 |
oct | 1756162355553 |
9 | 426532108048 |
10 | 135053040491 |
11 | 52303a14256 |
12 | 22210ba688b |
13 | c973a14715 |
14 | 67726164d5 |
15 | 37a6795a7b |
hex | 1f71c9db6b |
135053040491 has 2 divisors, whose sum is σ = 135053040492. Its totient is φ = 135053040490.
The previous prime is 135053040461. The next prime is 135053040527. The reversal of 135053040491 is 194040350531.
It is a weak prime.
It is an emirp because it is prime and its reverse (194040350531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135053040491 - 230 = 133979298667 is a prime.
It is a super-3 number, since 3×1350530404913 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (135053040461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67526520245 + 67526520246.
It is an arithmetic number, because the mean of its divisors is an integer number (67526520246).
Almost surely, 2135053040491 is an apocalyptic number.
135053040491 is a deficient number, since it is larger than the sum of its proper divisors (1).
135053040491 is an equidigital number, since it uses as much as digits as its factorization.
135053040491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 135053040491 in words is "one hundred thirty-five billion, fifty-three million, forty thousand, four hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •