Base | Representation |
---|---|
bin | 1100010010000111101100… |
… | …1101110111100000010101 |
3 | 1202211002220122022222221011 |
4 | 3010201323031313200111 |
5 | 3232233122232131123 |
6 | 44420152052252221 |
7 | 2562510334250443 |
oct | 304417315674025 |
9 | 52732818288834 |
10 | 13505444411413 |
11 | 4337699314059 |
12 | 1621542011071 |
13 | 76c733a55ab6 |
14 | 34994a351b93 |
15 | 186493258e0d |
hex | c487b377815 |
13505444411413 has 16 divisors (see below), whose sum is σ = 13865609387520. Its totient is φ = 13147385981184.
The previous prime is 13505444411411. The next prime is 13505444411419. The reversal of 13505444411413 is 31411444450531.
13505444411413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13505444411413 - 21 = 13505444411411 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13505444411411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101993433 + ... + 102125761.
It is an arithmetic number, because the mean of its divisors is an integer number (866600586720).
Almost surely, 213505444411413 is an apocalyptic number.
It is an amenable number.
13505444411413 is a deficient number, since it is larger than the sum of its proper divisors (360164976107).
13505444411413 is a wasteful number, since it uses less digits than its factorization.
13505444411413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140268.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 13505444411413 its reverse (31411444450531), we get a palindrome (44916888861944).
The spelling of 13505444411413 in words is "thirteen trillion, five hundred five billion, four hundred forty-four million, four hundred eleven thousand, four hundred thirteen".
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