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135064413163 = 896915059027
BaseRepresentation
bin111110111001001110…
…1110110001111101011
3110220121212112002102201
41331302131312033223
54203102442210123
6142014151041031
712521010366211
oct1756235661753
9426555462381
10135064413163
115230a381759
1222214970177
13c976197004
146773d36cb1
1537a77905ad
hex1f727763eb

135064413163 has 4 divisors (see below), whose sum is σ = 135079481160. Its totient is φ = 135049345168.

The previous prime is 135064413073. The next prime is 135064413167. The reversal of 135064413163 is 361314460531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 361314460531 = 400601901931.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135064413163 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135064413167) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7520545 + ... + 7538482.

It is an arithmetic number, because the mean of its divisors is an integer number (33769870290).

Almost surely, 2135064413163 is an apocalyptic number.

135064413163 is a deficient number, since it is larger than the sum of its proper divisors (15067997).

135064413163 is an equidigital number, since it uses as much as digits as its factorization.

135064413163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15067996.

The product of its (nonzero) digits is 77760, while the sum is 37.

Adding to 135064413163 its reverse (361314460531), we get a palindrome (496378873694).

The spelling of 135064413163 in words is "one hundred thirty-five billion, sixty-four million, four hundred thirteen thousand, one hundred sixty-three".

Divisors: 1 8969 15059027 135064413163