Base | Representation |
---|---|
bin | 11110101101011101101010… |
… | …111011001101110011100011 |
3 | 122201020011000000102111020021 |
4 | 132231131222323031303203 |
5 | 120200403402344342001 |
6 | 1155132143303054311 |
7 | 40310112143212123 |
oct | 3655355273156343 |
9 | 581204000374207 |
10 | 135065630465251 |
11 | 3a044015275712 |
12 | 1319475a441397 |
13 | 5a49832739775 |
14 | 254d2d60d2c83 |
15 | 10935789adba1 |
hex | 7ad76aecdce3 |
135065630465251 has 2 divisors, whose sum is σ = 135065630465252. Its totient is φ = 135065630465250.
The previous prime is 135065630465209. The next prime is 135065630465267. The reversal of 135065630465251 is 152564036560531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135065630465251 - 217 = 135065630334179 is a prime.
It is not a weakly prime, because it can be changed into another prime (135065630469251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67532815232625 + 67532815232626.
It is an arithmetic number, because the mean of its divisors is an integer number (67532815232626).
Almost surely, 2135065630465251 is an apocalyptic number.
135065630465251 is a deficient number, since it is larger than the sum of its proper divisors (1).
135065630465251 is an equidigital number, since it uses as much as digits as its factorization.
135065630465251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720000, while the sum is 52.
The spelling of 135065630465251 in words is "one hundred thirty-five trillion, sixty-five billion, six hundred thirty million, four hundred sixty-five thousand, two hundred fifty-one".
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